(3y+2)+(2y+1)=63

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Solution for (3y+2)+(2y+1)=63 equation:


Simplifying
(3y + 2) + (2y + 1) = 63

Reorder the terms:
(2 + 3y) + (2y + 1) = 63

Remove parenthesis around (2 + 3y)
2 + 3y + (2y + 1) = 63

Reorder the terms:
2 + 3y + (1 + 2y) = 63

Remove parenthesis around (1 + 2y)
2 + 3y + 1 + 2y = 63

Reorder the terms:
2 + 1 + 3y + 2y = 63

Combine like terms: 2 + 1 = 3
3 + 3y + 2y = 63

Combine like terms: 3y + 2y = 5y
3 + 5y = 63

Solving
3 + 5y = 63

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 5y = 63 + -3

Combine like terms: 3 + -3 = 0
0 + 5y = 63 + -3
5y = 63 + -3

Combine like terms: 63 + -3 = 60
5y = 60

Divide each side by '5'.
y = 12

Simplifying
y = 12

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