(3y+2)(6y-6)=0

Solution for (3y+2)(6y-6)=0 equation:

(3y+2)(6y-6)=0

We multiply parentheses ..

(+18y^2-18y+12y-12)=0

We get rid of parentheses

18y^2-18y+12y-12=0

We add all the numbers together, and all the variables

18y^2-6y-12=0

a = 18; b = -6; c = -12;
Δ = b2-4ac
Δ = -62-4·18·(-12)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-30}{2*18}=\frac{-24}{36}
=-2/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+30}{2*18}=\frac{36}{36}
=1
$