(3y+13)+(3y+29)=180

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Solution for (3y+13)+(3y+29)=180 equation:



(3y+13)+(3y+29)=180
We move all terms to the left:
(3y+13)+(3y+29)-(180)=0
We get rid of parentheses
3y+3y+13+29-180=0
We add all the numbers together, and all the variables
6y-138=0
We move all terms containing y to the left, all other terms to the right
6y=138
y=138/6
y=23

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