(3y+11)=(4y-22)

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Solution for (3y+11)=(4y-22) equation: 



(3y+11)=(4y-22)

We move all terms to the left:

(3y+11)-((4y-22))=0

We get rid of parentheses

3y-((4y-22))+11=0



We calculate terms in parentheses: -((4y-22)), so:

(4y-22)

We get rid of parentheses

4y-22

Back to the equation:

-(4y-22)



We get rid of parentheses

3y-4y+22+11=0

We add all the numbers together, and all the variables

-1y+33=0

We move all terms containing y to the left, all other terms to the right

-y=-33

y=-33/-1

y=+33

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