(3y+11)=(11y+15)

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Solution for (3y+11)=(11y+15) equation: 



(3y+11)=(11y+15)

We move all terms to the left:

(3y+11)-((11y+15))=0

We get rid of parentheses

3y-((11y+15))+11=0



We calculate terms in parentheses: -((11y+15)), so:

(11y+15)

We get rid of parentheses

11y+15

Back to the equation:

-(11y+15)



We get rid of parentheses

3y-11y-15+11=0

We add all the numbers together, and all the variables

-8y-4=0

We move all terms containing y to the left, all other terms to the right

-8y=4

y=4/-8

y=-1/2

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