(3y+1)=-5(y-1)-140

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Solution for (3y+1)=-5(y-1)-140 equation:


Simplifying
(3y + 1) = -5(y + -1) + -140

Reorder the terms:
(1 + 3y) = -5(y + -1) + -140

Remove parenthesis around (1 + 3y)
1 + 3y = -5(y + -1) + -140

Reorder the terms:
1 + 3y = -5(-1 + y) + -140
1 + 3y = (-1 * -5 + y * -5) + -140
1 + 3y = (5 + -5y) + -140

Reorder the terms:
1 + 3y = 5 + -140 + -5y

Combine like terms: 5 + -140 = -135
1 + 3y = -135 + -5y

Solving
1 + 3y = -135 + -5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '5y' to each side of the equation.
1 + 3y + 5y = -135 + -5y + 5y

Combine like terms: 3y + 5y = 8y
1 + 8y = -135 + -5y + 5y

Combine like terms: -5y + 5y = 0
1 + 8y = -135 + 0
1 + 8y = -135

Add '-1' to each side of the equation.
1 + -1 + 8y = -135 + -1

Combine like terms: 1 + -1 = 0
0 + 8y = -135 + -1
8y = -135 + -1

Combine like terms: -135 + -1 = -136
8y = -136

Divide each side by '8'.
y = -17

Simplifying
y = -17

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