(3y+1)+(3y+1)+40=0

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Solution for (3y+1)+(3y+1)+40=0 equation:


Simplifying
(3y + 1) + (3y + 1) + 40 = 0

Reorder the terms:
(1 + 3y) + (3y + 1) + 40 = 0

Remove parenthesis around (1 + 3y)
1 + 3y + (3y + 1) + 40 = 0

Reorder the terms:
1 + 3y + (1 + 3y) + 40 = 0

Remove parenthesis around (1 + 3y)
1 + 3y + 1 + 3y + 40 = 0

Reorder the terms:
1 + 1 + 40 + 3y + 3y = 0

Combine like terms: 1 + 1 = 2
2 + 40 + 3y + 3y = 0

Combine like terms: 2 + 40 = 42
42 + 3y + 3y = 0

Combine like terms: 3y + 3y = 6y
42 + 6y = 0

Solving
42 + 6y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-42' to each side of the equation.
42 + -42 + 6y = 0 + -42

Combine like terms: 42 + -42 = 0
0 + 6y = 0 + -42
6y = 0 + -42

Combine like terms: 0 + -42 = -42
6y = -42

Divide each side by '6'.
y = -7

Simplifying
y = -7

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