(3y+1)(3y-1)=

Solution for (3y+1)(3y-1)= equation:

Simplifying
(3y + 1)(3y + -1) = 0

Reorder the terms:
(1 + 3y)(3y + -1) = 0

Reorder the terms:
(1 + 3y)(-1 + 3y) = 0

Multiply (1 + 3y) * (-1 + 3y)
(1(-1 + 3y) + 3y * (-1 + 3y)) = 0
((-1 * 1 + 3y * 1) + 3y * (-1 + 3y)) = 0
((-1 + 3y) + 3y * (-1 + 3y)) = 0
(-1 + 3y + (-1 * 3y + 3y * 3y)) = 0
(-1 + 3y + (-3y + 9y2)) = 0

Combine like terms: 3y + -3y = 0
(-1 + 0 + 9y2) = 0
(-1 + 9y2) = 0

Solving
-1 + 9y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 9y2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 9y2 = 0 + 1
9y2 = 0 + 1

Combine like terms: 0 + 1 = 1
9y2 = 1

Divide each side by '9'.
y2 = 0.1111111111

Simplifying
y2 = 0.1111111111

Take the square root of each side:
y = {-0.333333333, 0.333333333}