(3y)/2+10=73

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Solution for (3y)/2+10=73 equation: 



(3y)/2+10=73

We move all terms to the left:

(3y)/2+10-(73)=0

We add all the numbers together, and all the variables

3y/2-63=0

We multiply all the terms by the denominator


3y-63*2=0

We add all the numbers together, and all the variables

3y-126=0

We move all terms containing y to the left, all other terms to the right

3y=126

y=126/3

y=42

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