(3y)/(2)-5=10

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Solution for (3y)/(2)-5=10 equation: 



(3y)/(2)-5=10

We move all terms to the left:

(3y)/(2)-5-(10)=0

We add all the numbers together, and all the variables

3y/2-15=0

We multiply all the terms by the denominator


3y-15*2=0

We add all the numbers together, and all the variables

3y-30=0

We move all terms containing y to the left, all other terms to the right

3y=30

y=30/3

y=10

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