(3y)(2y-1)(y/3)

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Solution for (3y)(2y-1)(y/3) equation: 


y in (-oo:+oo)

3*y*(y/3)*(2*y-1) = 0

y^2*(2*y-1) = 0

( 2*y-1 )

2*y-1 = 0 // + 1

2*y = 1 // : 2

y = 1/2

( y^2 )

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in { 1/2, 0 }

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