(3x=10)+(x-30)=180

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Solution for (3x=10)+(x-30)=180 equation: 



(3x=10)+(x-30)=180

We move all terms to the left:

(3x-(10)+(x-30))=0



We calculate terms in parentheses: +(3x-10+(x-30)), so:

3x-10+(x-30)

determiningTheFunctionDomain
3x+(x-30)-10

We get rid of parentheses

3x+x-30-10

We add all the numbers together, and all the variables

4x-40

Back to the equation:

+(4x-40)



We get rid of parentheses

4x-40=0

We move all terms containing x to the left, all other terms to the right

4x=40

x=40/4

x=10

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