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(3x/7)=(6/5)
We move all terms to the left:
(3x/7)-((6/5))=0
We add all the numbers together, and all the variables
(+3x/7)-((+6/5))=0
We get rid of parentheses
3x/7-((+6/5))=0
We calculate fractions
15x^2/()+()/()=0
We add all the numbers together, and all the variables
15x^2/()+1=0
We multiply all the terms by the denominator
15x^2+1*()=0
We add all the numbers together, and all the variables
15x^2=0
a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{30}=0$
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