(3x/7)-1=(2/3)(6x-2)

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Solution for (3x/7)-1=(2/3)(6x-2) equation: 


x in (-oo:+oo)

(3*x)/7-1 = (2/3)*(6*x-2) // - (2/3)*(6*x-2)

(3*x)/7-((2/3)*(6*x-2))-1 = 0

(-2/3)*(6*x-2)+(3*x)/7-1 = 0

(3*x)/7-2/3*(6*x-2)-1 = 0

(-2/3*7*(6*x-2))/7+(3*x)/7+(-1*7)/7 = 0

3*x-2/3*7*(6*x-2)-1*7 = 0

28/3-25*x-7 = 0

7/3-25*x = 0

(7/3-25*x)/7 = 0

(7/3-25*x)/7 = 0 // * 7

7/3-25*x = 0

7/3-25*x = 0 // - 7/3

-25*x = -7/3 // : -25

x = -7/3/(-25)

x = 7/75

x = 7/75

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