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(3x/5)-(4/5)(x+1)=2-(3/10)(3x-4)
We move all terms to the left:
(3x/5)-(4/5)(x+1)-(2-(3/10)(3x-4))=0
Domain of the equation: 5)(x+1)!=0
x∈R
Domain of the equation: 10)(3x-4))!=0We add all the numbers together, and all the variables
x∈R
(+3x/5)-(+4/5)(x+1)-(2-(+3/10)(3x-4))=0
We get rid of parentheses
3x/5-(+4/5)(x+1)-(2-(+3/10)(3x-4))=0
We multiply parentheses ..
-(+4x^2+4/5*1)+3x/5-(2-(+3/10)(3x-4))=0
We calculate fractions
(-(+4x^2+4*10)(3x-4)))/250x^2+30x^2/250x^2+()/250x^2=0
We can not solve this equation
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