(3x/4)+(7x/2)=17

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Solution for (3x/4)+(7x/2)=17 equation: 



(3x/4)+(7x/2)=17

We move all terms to the left:

(3x/4)+(7x/2)-(17)=0

We add all the numbers together, and all the variables

(+3x/4)+(+7x/2)-17=0

We get rid of parentheses

3x/4+7x/2-17=0

We calculate fractions

There is no solution for this equation

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