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(3x/2)+7x-7=3(2x+1)
We move all terms to the left:
(3x/2)+7x-7-(3(2x+1))=0
We add all the numbers together, and all the variables
(+3x/2)+7x-(3(2x+1))-7=0
We add all the numbers together, and all the variables
7x+(+3x/2)-(3(2x+1))-7=0
We get rid of parentheses
7x+3x/2-(3(2x+1))-7=0
We multiply all the terms by the denominator
7x*2+3x-((3(2x+1)))*2-7*2=0
We add all the numbers together, and all the variables
3x+7x*2-((3(2x+1)))*2-14=0
Wy multiply elements
3x+14x-((3(2x+1)))*2-14=0
We add all the numbers together, and all the variables
17x-((3(2x+1)))*2-14=0
We move all terms containing x to the left, all other terms to the right
17x-((3(2x+1)))*2=14
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