(3x/2)+(x/6)=-(5/3)

Solution for (3x/2)+(x/6)=-(5/3) equation:

(3x/2)+(x/6)=-(5/3)

We move all terms to the left:

(3x/2)+(x/6)-(-(5/3))=0

We add all the numbers together, and all the variables

(+3x/2)+(+x/6)-(-(+5/3))=0

We get rid of parentheses

3x/2+x/6-(-(+5/3))=0

We calculate fractions


162x^2/()+18x^2/()+()/()=0

We add all the numbers together, and all the variables

162x^2/()+18x^2/()+1=0

We multiply all the terms by the denominator


162x^2+18x^2+1*()=0

We add all the numbers together, and all the variables

180x^2=0

a = 180; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·180·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{360}=0$