(3x/2)+(7x/2)=1

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Solution for (3x/2)+(7x/2)=1 equation:



(3x/2)+(7x/2)=1
We move all terms to the left:
(3x/2)+(7x/2)-(1)=0
We add all the numbers together, and all the variables
(+3x/2)+(+7x/2)-1=0
We get rid of parentheses
3x/2+7x/2-1=0
We multiply all the terms by the denominator
3x+7x-1*2=0
We add all the numbers together, and all the variables
10x-2=0
We move all terms containing x to the left, all other terms to the right
10x=2
x=2/10
x=1/5

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