(3x-9)/10-(x/5)=(x/10)+6

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Solution for (3x-9)/10-(x/5)=(x/10)+6 equation: 


x in (-oo:+oo)

(3*x-9)/10-(x/5) = x/10+6 // - x/10+6

(3*x-9)/10-(x/5)-(x/10)-6 = 0

(3*x-9)/10-x/5-x/10-6 = 0

(5*(3*x-9))/(5*10)+(10*(-x))/(5*10)+(5*(-x))/(5*10)+(-6*5*10)/(5*10) = 0

5*(3*x-9)+10*(-x)+5*(-x)-6*5*10 = 0

5*x-5*x-300-45 = 0

-300-45 = 0

-345 = 0

-345/(5*10) = 0

-345/(5*10) = 0 // * 5*10

-345 = 0

x belongs to the empty set

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