(3x-8)=(2x+3)+(x+12)

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Solution for (3x-8)=(2x+3)+(x+12) equation:


Simplifying
(3x + -8) = (2x + 3) + (x + 12)

Reorder the terms:
(-8 + 3x) = (2x + 3) + (x + 12)

Remove parenthesis around (-8 + 3x)
-8 + 3x = (2x + 3) + (x + 12)

Reorder the terms:
-8 + 3x = (3 + 2x) + (x + 12)

Remove parenthesis around (3 + 2x)
-8 + 3x = 3 + 2x + (x + 12)

Reorder the terms:
-8 + 3x = 3 + 2x + (12 + x)

Remove parenthesis around (12 + x)
-8 + 3x = 3 + 2x + 12 + x

Reorder the terms:
-8 + 3x = 3 + 12 + 2x + x

Combine like terms: 3 + 12 = 15
-8 + 3x = 15 + 2x + x

Combine like terms: 2x + x = 3x
-8 + 3x = 15 + 3x

Add '-3x' to each side of the equation.
-8 + 3x + -3x = 15 + 3x + -3x

Combine like terms: 3x + -3x = 0
-8 + 0 = 15 + 3x + -3x
-8 = 15 + 3x + -3x

Combine like terms: 3x + -3x = 0
-8 = 15 + 0
-8 = 15

Solving
-8 = 15

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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