(3x-8)/(12)+x=(3x+8)/(3)+1

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Solution for (3x-8)/(12)+x=(3x+8)/(3)+1 equation: 



(3x-8)/(12)+x=(3x+8)/(3)+1

We move all terms to the left:

(3x-8)/(12)+x-((3x+8)/(3)+1)=0

We add all the numbers together, and all the variables

x+(3x-8)/12-((3x+8)/3+1)=0

We calculate fractions


x+(9x-24)/()+(-((3x+8)*12)/()=0



We calculate terms in parentheses: +(-((3x+8)*12)/(), so:

-((3x+8)*12)/(

We multiply all the terms by the denominator


-((3x+8)*12)



We calculate terms in parentheses: -((3x+8)*12), so:

(3x+8)*12

We multiply parentheses

36x+96

Back to the equation:

-(36x+96)



We get rid of parentheses

-36x-96

Back to the equation:

+(-36x-96)



We get rid of parentheses

x+(9x-24)/()-36x-96=0

We multiply all the terms by the denominator


x*()+(9x-24)-36x*()-96*()=0

We add all the numbers together, and all the variables

x*()+(9x-24)-36x*()=0

We get rid of parentheses

x*()+9x-36x*()-24=0

We add all the numbers together, and all the variables

9x+x*()-36x*()-24=0

We move all terms containing x to the left, all other terms to the right

9x+x*()-36x*()=24

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