(3x-8)(3x=2)-(4x-11)(2x+1)=(x-3)(x+7)

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Solution for (3x-8)(3x=2)-(4x-11)(2x+1)=(x-3)(x+7) equation:



(3x-8)(3x=2)-(4x-11)(2x+1)=(x-3)(x+7)
We move all terms to the left:
(3x-8)(3x-(2)-(4x-11)(2x+1))=0
We multiply parentheses ..
(3x-8)(3x-2-(+8x^2+4x-22x-11))=0
We calculate terms in parentheses: +(3x-8)(3x-2-(+8x^2+4x-22x-11)), so:
3x-8)(3x-2-(+8x^2+4x-22x-11)
determiningTheFunctionDomain -(+8x^2+4x-22x-11)+3x-8)(3x-2
We get rid of parentheses
-8x^2-4x+22x+3x-8)(3x+11-2
We add all the numbers together, and all the variables
-8x^2+21x-8)(3x+9
Back to the equation:
+(-8x^2+21x-8)(3x+9)

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