(3x-70)(x+1)=180

Solution for (3x-70)(x+1)=180 equation:

(3x-70)(x+1)=180

We move all terms to the left:

(3x-70)(x+1)-(180)=0

We multiply parentheses ..

(+3x^2+3x-70x-70)-180=0

We get rid of parentheses

3x^2+3x-70x-70-180=0

We add all the numbers together, and all the variables

3x^2-67x-250=0

a = 3; b = -67; c = -250;
Δ = b2-4ac
Δ = -672-4·3·(-250)
Δ = 7489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-67)-\sqrt{7489}}{2*3}=\frac{67-\sqrt{7489}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-67)+\sqrt{7489}}{2*3}=\frac{67+\sqrt{7489}}{6}
$