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(3x-7+2x)=(4x+5)
We move all terms to the left:
(3x-7+2x)-((4x+5))=0
We add all the numbers together, and all the variables
(5x-7)-((4x+5))=0
We get rid of parentheses
5x-((4x+5))-7=0
We calculate terms in parentheses: -((4x+5)), so:We get rid of parentheses
(4x+5)
We get rid of parentheses
4x+5
Back to the equation:
-(4x+5)
5x-4x-5-7=0
We add all the numbers together, and all the variables
x-12=0
We move all terms containing x to the left, all other terms to the right
x=12
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