(3x-7)/12=(3x+3)/18

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Solution for (3x-7)/12=(3x+3)/18 equation: 



(3x-7)/12=(3x+3)/18

We move all terms to the left:

(3x-7)/12-((3x+3)/18)=0

We calculate fractions


3x/()+(-((3x+3)*12)/()=0



We calculate terms in parentheses: +(-((3x+3)*12)/(), so:

-((3x+3)*12)/(

We multiply all the terms by the denominator


-((3x+3)*12)



We calculate terms in parentheses: -((3x+3)*12), so:

(3x+3)*12

We multiply parentheses

36x+36

Back to the equation:

-(36x+36)



We get rid of parentheses

-36x-36

Back to the equation:

+(-36x-36)



We get rid of parentheses

3x/()-36x-36=0

We multiply all the terms by the denominator


3x-36x*()-36*()=0

We add all the numbers together, and all the variables

3x-36x*()=0

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