(3x-7)+(2x+11)=(7x-14)

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Solution for (3x-7)+(2x+11)=(7x-14) equation: 



(3x-7)+(2x+11)=(7x-14)

We move all terms to the left:

(3x-7)+(2x+11)-((7x-14))=0

We get rid of parentheses

3x+2x-((7x-14))-7+11=0



We calculate terms in parentheses: -((7x-14)), so:

(7x-14)

We get rid of parentheses

7x-14

Back to the equation:

-(7x-14)



We add all the numbers together, and all the variables

5x-(7x-14)+4=0

We get rid of parentheses

5x-7x+14+4=0

We add all the numbers together, and all the variables

-2x+18=0

We move all terms containing x to the left, all other terms to the right

-2x=-18

x=-18/-2

x=+9

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