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(3x-7)(4x+12)=180
We move all terms to the left:
(3x-7)(4x+12)-(180)=0
We multiply parentheses ..
(+12x^2+36x-28x-84)-180=0
We get rid of parentheses
12x^2+36x-28x-84-180=0
We add all the numbers together, and all the variables
12x^2+8x-264=0
a = 12; b = 8; c = -264;
Δ = b2-4ac
Δ = 82-4·12·(-264)
Δ = 12736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12736}=\sqrt{64*199}=\sqrt{64}*\sqrt{199}=8\sqrt{199}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{199}}{2*12}=\frac{-8-8\sqrt{199}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{199}}{2*12}=\frac{-8+8\sqrt{199}}{24} $
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