(3x-65)/(1x-65)=3

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Solution for (3x-65)/(1x-65)=3 equation: 


D( x )

1*x-65 = 0

1*x-65 = 0

1*x-65 = 0

x-65 = 0

x-65 = 0 // + 65

x = 65

x in (-oo:65) U (65:+oo)

(3*x-65)/(1*x-65) = 3 // - 3

(3*x-65)/(1*x-65)-3 = 0

(3*x-65)/(x-65)-3 = 0

(3*x-65)/(x-65)+(-3*(x-65))/(x-65) = 0

3*x-3*(x-65)-65 = 0

130 = 0

130/(x-65) = 0

130/(x-65) = 0 // * x-65

130 = 0

130 = 0

x belongs to the empty set

x belongs to the empty set

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