(3x-65)/(1x-65)=16

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Solution for (3x-65)/(1x-65)=16 equation: 


D( x )

1*x-65 = 0

1*x-65 = 0

1*x-65 = 0

x-65 = 0

x-65 = 0 // + 65

x = 65

x in (-oo:65) U (65:+oo)

(3*x-65)/(1*x-65) = 16 // - 16

(3*x-65)/(1*x-65)-16 = 0

(3*x-65)/(x-65)-16 = 0

(3*x-65)/(x-65)+(-16*(x-65))/(x-65) = 0

3*x-16*(x-65)-65 = 0

975-13*x = 0

(975-13*x)/(x-65) = 0

(975-13*x)/(x-65) = 0 // * x-65

975-13*x = 0

975-13*x = 0 // - 975

-13*x = -975 // : -13

x = -975/(-13)

x = 75

x = 75

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