(3x-6)+(4x-2)+(9x-8)=180

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Solution for (3x-6)+(4x-2)+(9x-8)=180 equation: 



(3x-6)+(4x-2)+(9x-8)=180

We move all terms to the left:

(3x-6)+(4x-2)+(9x-8)-(180)=0

We get rid of parentheses

3x+4x+9x-6-2-8-180=0

We add all the numbers together, and all the variables

16x-196=0

We move all terms containing x to the left, all other terms to the right

16x=196

x=196/16

x=12+1/4

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