(3x-6)(x+8)=0

Solution for (3x-6)(x+8)=0 equation:

(3x-6)(x+8)=0

We multiply parentheses ..

(+3x^2+24x-6x-48)=0

We get rid of parentheses

3x^2+24x-6x-48=0

We add all the numbers together, and all the variables

3x^2+18x-48=0

a = 3; b = 18; c = -48;
Δ = b2-4ac
Δ = 182-4·3·(-48)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-30}{2*3}=\frac{-48}{6}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+30}{2*3}=\frac{12}{6}
=2
$