(3x-6)(8x+4)=0

Solution for (3x-6)(8x+4)=0 equation:

(3x-6)(8x+4)=0

We multiply parentheses ..

(+24x^2+12x-48x-24)=0

We get rid of parentheses

24x^2+12x-48x-24=0

We add all the numbers together, and all the variables

24x^2-36x-24=0

a = 24; b = -36; c = -24;
Δ = b2-4ac
Δ = -362-4·24·(-24)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-60}{2*24}=\frac{-24}{48}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+60}{2*24}=\frac{96}{48}
=2
$