(3x-59)+(2x+4)+(2x-1)+(2x+4)=180

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Solution for (3x-59)+(2x+4)+(2x-1)+(2x+4)=180 equation: 



(3x-59)+(2x+4)+(2x-1)+(2x+4)=180

We move all terms to the left:

(3x-59)+(2x+4)+(2x-1)+(2x+4)-(180)=0

We get rid of parentheses

3x+2x+2x+2x-59+4-1+4-180=0

We add all the numbers together, and all the variables

9x-232=0

We move all terms containing x to the left, all other terms to the right

9x=232

x=232/9

x=25+7/9

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