(3x-5)/6=(x+2)/3

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Solution for (3x-5)/6=(x+2)/3 equation:



(3x-5)/6=(x+2)/3
We move all terms to the left:
(3x-5)/6-((x+2)/3)=0
We calculate fractions
3x/()+(-((x+2)*6)/()=0
We calculate terms in parentheses: +(-((x+2)*6)/(), so:
-((x+2)*6)/(
We multiply all the terms by the denominator
-((x+2)*6)
We calculate terms in parentheses: -((x+2)*6), so:
(x+2)*6
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
We get rid of parentheses
-6x-12
Back to the equation:
+(-6x-12)
We get rid of parentheses
3x/()-6x-12=0
We multiply all the terms by the denominator
3x-6x*()-12*()=0
We add all the numbers together, and all the variables
3x-6x*()=0

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