(3x-5)/2=(x-4)/3

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Solution for (3x-5)/2=(x-4)/3 equation: 



(3x-5)/2=(x-4)/3

We move all terms to the left:

(3x-5)/2-((x-4)/3)=0

We calculate fractions


3x/()+(-((x-4)*2)/()=0



We calculate terms in parentheses: +(-((x-4)*2)/(), so:

-((x-4)*2)/(

We multiply all the terms by the denominator


-((x-4)*2)



We calculate terms in parentheses: -((x-4)*2), so:

(x-4)*2

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We get rid of parentheses

-2x+8

Back to the equation:

+(-2x+8)



We get rid of parentheses

3x/()-2x+8=0

We multiply all the terms by the denominator


3x-2x*()+8*()=0

We add all the numbers together, and all the variables

3x-2x*()=0

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