(3x-5)/12=(2x+7)/8

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Solution for (3x-5)/12=(2x+7)/8 equation: 



(3x-5)/12=(2x+7)/8

We move all terms to the left:

(3x-5)/12-((2x+7)/8)=0

We calculate fractions


3x/()+(-((2x+7)*12)/()=0



We calculate terms in parentheses: +(-((2x+7)*12)/(), so:

-((2x+7)*12)/(

We multiply all the terms by the denominator


-((2x+7)*12)



We calculate terms in parentheses: -((2x+7)*12), so:

(2x+7)*12

We multiply parentheses

24x+84

Back to the equation:

-(24x+84)



We get rid of parentheses

-24x-84

Back to the equation:

+(-24x-84)



We get rid of parentheses

3x/()-24x-84=0

We multiply all the terms by the denominator


3x-24x*()-84*()=0

We add all the numbers together, and all the variables

3x-24x*()=0

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