(3x-5)+(x-5)+90+(4x+10)=90

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Solution for (3x-5)+(x-5)+90+(4x+10)=90 equation: 



(3x-5)+(x-5)+90+(4x+10)=90

We move all terms to the left:

(3x-5)+(x-5)+90+(4x+10)-(90)=0

We add all the numbers together, and all the variables

(3x-5)+(x-5)+(4x+10)=0

We get rid of parentheses

3x+x+4x-5-5+10=0

We add all the numbers together, and all the variables

8x=0

x=0/8

x=0

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