(3x-5)+(x-1)=(7x-27)

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Solution for (3x-5)+(x-1)=(7x-27) equation:



(3x-5)+(x-1)=(7x-27)
We move all terms to the left:
(3x-5)+(x-1)-((7x-27))=0
We get rid of parentheses
3x+x-((7x-27))-5-1=0
We calculate terms in parentheses: -((7x-27)), so:
(7x-27)
We get rid of parentheses
7x-27
Back to the equation:
-(7x-27)
We add all the numbers together, and all the variables
4x-(7x-27)-6=0
We get rid of parentheses
4x-7x+27-6=0
We add all the numbers together, and all the variables
-3x+21=0
We move all terms containing x to the left, all other terms to the right
-3x=-21
x=-21/-3
x=+7

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