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(3x-5)+(x)+(x-5)=180
We move all terms to the left:
(3x-5)+(x)+(x-5)-(180)=0
We add all the numbers together, and all the variables
x+(3x-5)+(x-5)-180=0
We get rid of parentheses
x+3x+x-5-5-180=0
We add all the numbers together, and all the variables
5x-190=0
We move all terms containing x to the left, all other terms to the right
5x=190
x=190/5
x=38
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