(3x-5)+(7x+3)+(6x-3)=180

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Solution for (3x-5)+(7x+3)+(6x-3)=180 equation: 



(3x-5)+(7x+3)+(6x-3)=180

We move all terms to the left:

(3x-5)+(7x+3)+(6x-3)-(180)=0

We get rid of parentheses

3x+7x+6x-5+3-3-180=0

We add all the numbers together, and all the variables

16x-185=0

We move all terms containing x to the left, all other terms to the right

16x=185

x=185/16

x=11+9/16

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