(3x-5)+(19-x)+(2x)=0

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Solution for (3x-5)+(19-x)+(2x)=0 equation: 



(3x-5)+(19-x)+(2x)=0

We add all the numbers together, and all the variables

(3x-5)+(-1x+19)+2x=0

We add all the numbers together, and all the variables

2x+(3x-5)+(-1x+19)=0

We get rid of parentheses

2x+3x-1x-5+19=0

We add all the numbers together, and all the variables

4x+14=0

We move all terms containing x to the left, all other terms to the right

4x=-14

x=-14/4

x=-3+1/2

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