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(3x-5)(x-7)=0
We multiply parentheses ..
(+3x^2-21x-5x+35)=0
We get rid of parentheses
3x^2-21x-5x+35=0
We add all the numbers together, and all the variables
3x^2-26x+35=0
a = 3; b = -26; c = +35;
Δ = b2-4ac
Δ = -262-4·3·35
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-16}{2*3}=\frac{10}{6} =1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+16}{2*3}=\frac{42}{6} =7 $
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