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(3x-5)(5x+20)=135
We move all terms to the left:
(3x-5)(5x+20)-(135)=0
We multiply parentheses ..
(+15x^2+60x-25x-100)-135=0
We get rid of parentheses
15x^2+60x-25x-100-135=0
We add all the numbers together, and all the variables
15x^2+35x-235=0
a = 15; b = 35; c = -235;
Δ = b2-4ac
Δ = 352-4·15·(-235)
Δ = 15325
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15325}=\sqrt{25*613}=\sqrt{25}*\sqrt{613}=5\sqrt{613}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-5\sqrt{613}}{2*15}=\frac{-35-5\sqrt{613}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+5\sqrt{613}}{2*15}=\frac{-35+5\sqrt{613}}{30} $
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