(3x-42)+(2x-3)+(x-2)+(x+1)=360

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Solution for (3x-42)+(2x-3)+(x-2)+(x+1)=360 equation:



(3x-42)+(2x-3)+(x-2)+(x+1)=360
We move all terms to the left:
(3x-42)+(2x-3)+(x-2)+(x+1)-(360)=0
We get rid of parentheses
3x+2x+x+x-42-3-2+1-360=0
We add all the numbers together, and all the variables
7x-406=0
We move all terms containing x to the left, all other terms to the right
7x=406
x=406/7
x=58

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