(3x-4)=(9x+17)=(6x-31)

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Solution for (3x-4)=(9x+17)=(6x-31) equation: 



(3x-4)=(9x+17)=(6x-31)

We move all terms to the left:

(3x-4)-((9x+17))=0

We get rid of parentheses

3x-((9x+17))-4=0



We calculate terms in parentheses: -((9x+17)), so:

(9x+17)

We get rid of parentheses

9x+17

Back to the equation:

-(9x+17)



We get rid of parentheses

3x-9x-17-4=0

We add all the numbers together, and all the variables

-6x-21=0

We move all terms containing x to the left, all other terms to the right

-6x=21

x=21/-6

x=-3+1/2

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