(3x-4)=(2x+17)

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Solution for (3x-4)=(2x+17) equation: 



(3x-4)=(2x+17)

We move all terms to the left:

(3x-4)-((2x+17))=0

We get rid of parentheses

3x-((2x+17))-4=0



We calculate terms in parentheses: -((2x+17)), so:

(2x+17)

We get rid of parentheses

2x+17

Back to the equation:

-(2x+17)



We get rid of parentheses

3x-2x-17-4=0

We add all the numbers together, and all the variables

x-21=0

We move all terms containing x to the left, all other terms to the right

x=21

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