(3x-4)2=8x(x-3)+52

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Solution for (3x-4)2=8x(x-3)+52 equation: 



(3x-4)2=8x(x-3)+52

We move all terms to the left:

(3x-4)2-(8x(x-3)+52)=0

We multiply parentheses

6x-(8x(x-3)+52)-8=0



We calculate terms in parentheses: -(8x(x-3)+52), so:

8x(x-3)+52

We multiply parentheses

8x^2-24x+52

Back to the equation:

-(8x^2-24x+52)



We get rid of parentheses

-8x^2+6x+24x-52-8=0

We add all the numbers together, and all the variables

-8x^2+30x-60=0

a = -8; b = 30; c = -60;
Δ = b2-4ac
Δ = 302-4·(-8)·(-60)
Δ = -1020
Delta is less than zero, so there is no solution for the equation

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