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(3x-4)/(2)+6=x-4
We move all terms to the left:
(3x-4)/(2)+6-(x-4)=0
We get rid of parentheses
(3x-4)/2-x+4+6=0
We multiply all the terms by the denominator
(3x-4)-x*2+4*2+6*2=0
We add all the numbers together, and all the variables
(3x-4)-x*2+20=0
Wy multiply elements
(3x-4)-2x+20=0
We get rid of parentheses
3x-2x-4+20=0
We add all the numbers together, and all the variables
x+16=0
We move all terms containing x to the left, all other terms to the right
x=-16
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