(3x-4)+3x-4)=40

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Solution for (3x-4)+3x-4)=40 equation: 



(3x-4)+3x-4)=40

We move all terms to the left:

(3x-4)+3x-4)-(40)=0

We add all the numbers together, and all the variables

3x+(3x-4)=0

We get rid of parentheses

3x+3x-4=0

We add all the numbers together, and all the variables

6x-4=0

We move all terms containing x to the left, all other terms to the right

6x=4

x=4/6

x=2/3

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